got a typo in my previous post:
I was trying this:
$fname = 'hello';
function { sprintf("%s", $fname) }($fname='') {
Return "I named you : $fname";
}
echo $fname($fname);
But that doesn't matter...
Thanks,
waiting for your help.
Maxim Maletsky
Founder, Chief Developer
PHPBeginner.com (Where PHP Begins)
[EMAIL PROTECTED]
www.phpbeginner.com
-----Original Message-----
From: Maxim Maletsky
Sent: Friday, April 27, 2001 8:58 PM
To: 'PHP General List. (E-mail)'
Subject: [PHP] Variable (naming them) Functions.
Hello everyone:
I was wondering, does anyone of you know a method to declare a function
(give it a name) basing on a value acquired during run time?
I tried using the syntax as of a variable function call:
<snip>
$fname = 'hello';
function { sprintf("%s", $fname) }($arg='') {
Return "I named you : $fname";
}
echo $fname($fname);
# no luck...
function {$fname}($arg='') { ....
# nope...
function $fname($arg='') { ....
# neither...
</snip>
and so on... all parse errors...
Any way to do it?
I am looping an array with some function names checking if a function was
declared already, and if not then declare, if yes - give a different name.
I also went through these bibles:
http://www.php.net/manual/en/ref.funchand.php
<http://www.php.net/manual/en/ref.funchand.php>
but found nothing that helps.
Thanks in advance,
Sincerely,
Maxim Maletsky
Founder, Chief Developer
PHPBeginner.com (Where PHP Begins)
[EMAIL PROTECTED] <mailto:[EMAIL PROTECTED]>
www.phpbeginner.com <http://www.phpbeginner.com>
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