Martin Alterisio wrote:
2006/6/4, Rasmus Lerdorf <[EMAIL PROTECTED]>:
tedd wrote:
> Hi gang:
>
> Here's your opportunity to pound me again for not knowing the basics of
php.
>
> I vaguely remember something like this being discussed a while back,
but
can't find the reference.
>
> In any event, if one uses --
>
> for ($i="a"; $i<"z"; $i++)
> {
> echo($i);
> }
>
> -- it stops at "y"
>
> But, if you use --
>
> for ($i="a"; $i<="z"; $i++)
> {
> echo($i);
> }
>
> -- it prints considerably more characters after "z" than what one would
normally expect -- why is that?
>
> Just stopping at "z" would seem to make more sense, wouldn't it? After
all, when $i = "z" in the first expression, then wouldn't $i be equal
to "z"
in the second expression and thus halt the operation?
>
> What am I missing here?
It's a bit of a quirk. "z"++ is "aa" and "aa" < "z". I would guess
this would loop until until just before "za" which would be "yz".
What?
"z"++ < "z" returns true? =S
Is there a reason for this? Why aren't they handled like C chars?
Because PHP is not C. If you want them handled by their char codes,
then do so with chr() calls.
It's a bit like looping through the hexadecimal characters. You would
have the same effect. However instead of being base-16 with 0-9-a-f you
have base-26 using a-z.
0xF++ would be 0x10 which is greater than 0xF (0xF < 0x10). It's not the
same.
Sure it is. If you treat 0x10 as a string the same way he is treating
these as strings, then 0x10 is going to be smaller than 0xF.
The fact is that there is just no right answer for what "z"++ should do.
-Rasmus
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