I found this on google, does this LONG function do anything more then your
preg_match?
function isEmail($emailstr) {
// Make the email address lower case and remove whitespace
$emailstr = strtolower(trim($emailstr));
// Split it up into before and after the @ symbol
$email_components = explode('@', $emailstr);
// Check that there is only one @ symbol
if (count($email_components) != 2)
return FALSE;
// Check that the username is >= 1 char
if (strlen($email_components[0]) == 0)
return FALSE;
// Split the domain part into the dotted parts
$domain_components = explode('.', $email_components[1]);
// check there are at least 2
if (count($domain_components) < 2)
return FALSE;
// Check each domain part to ensure it doesn't start or end with
a bad char
foreach ($domain_components as $domain_component)
if ( strlen($domain_component) > 0 ) {
if ( preg_match('/[\.-]/', $domain_component[0])
|| preg_match('/[\.-]/',
$domain_component[strlen($domain_component)-1]) )
return FALSE;
} else
return FALSE;
// Check the last domain component has 2-6 chars (.uk to
.museum)
$domain_last = array_pop($domain_components);
if (strlen($domain_last) < 2 || strlen($domain_last) > 6)
return FALSE;
// Check for valid chars - Domains can only have A-Z, 0-9, .,
and the - chars,
// or be in the form [123.123.123.123]
if ( preg_match('/^\[(\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3})\]$/',
$email_components[1], $ipnum) )
return (ip2long($ipnum[1]) === false ? false : true);
if ( preg_match('/^[a-z0-9\.-]+$/', $email_components[1]) )
return TRUE;
// If we get here then it didn't pass
return FALSE;
}
/Peter
________________________________________
From: Dave Goodchild [mailto:[EMAIL PROTECTED]
Sent: Sunday, August 27, 2006 8:47 PM
To: Peter Lauri
Cc: [email protected]
Subject: Re: [PHP] Email with pregmatch
Try this:
preg_match("/^([a-zA-Z0-9.])+@([a-zA-Z0-9_-])+(\.[a-zA-Z0-9_-]+)+/",
$_POST['email']);
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