Well, it could be this, too:
switch( $_REQUEST['id'] ) {
case "white":
echo "Right color.";
break;
case "black":
echo "Right color.";
break;
default:
echo "Wrong color.";
break;
}
---
Jeremy C. Privett
Director of Product Development
Zend Certified Engineer
Completely Unique
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-----Original Message-----
From: Kevin Murphy [mailto:[EMAIL PROTECTED]
Sent: Friday, September 08, 2006 3:26 PM
To: php
Cc: JD
Subject: Re: [PHP] if statement with or comparison (newbie)
Shouldn't that be this instead:
if (($_REQUEST['id'] != "black") OR ($_REQUEST['id'] !=
"white")) {
echo "wrong color";
} else {
echo "right color";
}
--
Kevin Murphy
Webmaster: Information and Marketing Services
Western Nevada Community College
www.wncc.edu
775-445-3326
On Sep 8, 2006, at 2:28 PM, Prathaban Mookiah wrote:
> Let me rephrase it. Your color should be black or white to be the
> right
> colour. Is this correct?
>
> In that case you should change it to
>
> if ($_REQUEST['id'] != "black" AND $_REQUEST['id'] != "white") {
>
> echo "wrong color";
>
> } else (
>
> echo "right color";
>
> }
>
> ----- Original Message -----
> From: "JD" <[EMAIL PROTECTED]>
> To: <php-general@lists.php.net>
> Sent: Friday, September 08, 2006 5:03 PM
> Subject: [PHP] if statement with or comparison (newbie)
>
>
>> I'm trying to set up a simple conditional, something like this:
>>
>> If my_variable is NOT equal to (black or white)
>> echo "wrong color"
>> else
>> echo "right color"
>>
>> Here is what I have tried:
>>
>> if ($_REQUEST['id'] != ("black" or "white")) {
>>
>> echo "wrong color";
>>
>> } else (
>>
>> echo "right color";
>>
>> )
>>
>> However, no matter what I enter, I always get response "right color".
>>
>> I should add that if I change the if statement to:
>>
>> if ($_REQUEST['id'] != ("black"))
>>
>> then I get "right color" when I enter "black" and "wrong color" for
>> everything else.
>>
>> Would you please point out what's the trivial thing I'm missing
>> here...
>>
>> jd
>>
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>>
>>
>
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