Obviously I'm not quite understanding, maybe a further explanation is needed
to help me understand.
This is how I see it from what you said - am in in the right ballpark.
The function is returning a null value if there is no error, and I guess PHP
sees 'null' or "" as a value. So how do I get around this?
This is how I call the function.
if($result = ValidateString($orgname, 1)) { $formerror['orgname'] = $result;
}
If there is an error an error string will be returned (i.e. Error in field),
if not I want nothing returned.
Later on in the page I use - if(!$formerror) blah blah.
This is where the problem is because if null or "" is being returned then
$formerror has a value which breaks the above if.
I hope this helps.
Thanks
> -----Original Message-----
> From: Roman Neuhauser [mailto:[EMAIL PROTECTED]
> Sent: January 16, 2007 5:49 AM
> To: Beauford
> Cc: 'PHP'
> Subject: Re: [PHP] I lied, another question / problem
>
> # [EMAIL PROTECTED] / 2007-01-15 19:22:24 -0500:
> > > From: 'Roman Neuhauser' [mailto:[EMAIL PROTECTED] #
> > > [EMAIL PROTECTED] / 2007-01-15 18:33:31 -0500:
> > > > > From: Roman Neuhauser [mailto:[EMAIL PROTECTED] #
> > > > > [EMAIL PROTECTED] / 2007-01-15 16:31:32 -0500:
> > > > > > I have file which I use for validating which includes the
> > > > > > following
> > > > > > function:
> > > > > >
> > > > > > function invalidchar($strvalue) {
> > > > > > if(!ereg("^[[:alpha:][:space:]\'-.]*$", $strvalue)) {
> > > > >
> > > > > That regexp matches if $strvalue consists of zero or more
> > > > > ocurrences of a letter, a whitespace character, and any
> > > > > character whose numeric value lies between the
> numeric values of
> > > > > "'" and "." in your locale. Zero or more means it
> also matches
> > > > > an empty string.
>
> > > > All I want to accomplish here is to allow the user to enter
> > > a to z, A
> > > > to Z, and /\'-_. and a space. Is there a better way to do this?
> > >
> > > 1. Do you really want to let them enter backslashes, or
> are you trying
> > > to "escape" the apostrophe?
> > > 2. Does that mean that "/\'-_." (without the quotes) and
> " " (that's
> > > three spaces) are valid entries?
> >
> > Where do you see 3 spaces?
>
> That's a value the regexp will match. Is that intended?
>
> > In any event, I don't think this is the problem.
> > As I have said the code works fine on two other pages,
> which logically
> > suggests that there is something on this page that is
> causing a problem.
>
> You don't understand that single function, and it does
> something else than you think it does. I told you what it
> actually does, but you chose to ignore the information. I
> don't know how I could help you more.
>
> --
> How many Vietnam vets does it take to screw in a light bulb?
> You don't know, man. You don't KNOW.
> Cause you weren't THERE. http://bash.org/?255991
>
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