:|
if i want link 3,
$result = mysql_query("SELECT address FROM db.links WHERE link_id=3");
$foo = mysql_fetch_assoc($result);
echo '<a href="'.$foo['address'].'">this is link 3</a>';
On 3/7/07, StainOnRug <[EMAIL PROTECTED]> wrote:
Hello.. I searched for an answer on the simple quesiton but I am only
finding
complex answers... I simply just want to add a link in my database so when
my results display you can see the information.. and when they click the
link it takes them to the webpage of the article. I tried inserting
examplesite.com User sees this text but when the results page shows.. it
doesnt show the hyperlink.. Thank you all very much!
-Darren
Thanks again!
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