On 14 March 2007 22:52, Richard Lynch wrote:

> On Wed, March 14, 2007 6:52 am, Myron Turner wrote:
> > Richard Lynch wrote:
> > > On Tue, March 13, 2007 6:04 pm, Jonathan Kahan wrote:
> > > The = operator takes precedence, and $d is set to 0.
> > > 
> > But why?  According to the manual, the modulus operator has
> > precedence over the equals!  So shouldn't this expression  resolve
> > to:    ($s % $d) = 0 which gives an error?
> 
> Ya got me there.
> 
> I hadn't even checked the precedence list before answering.
> 
> Unless somebody has a rational explanation, I think this should be an
> error... 

When a similar anomaly involving the ! operator was reported 
(http://bugs.php.net/bug.php?id=17180), the response was that PHP is "smart" 
about such things and invokes the DWIM principle to silently alter the 
precedence of = in certain situations.  This resulted in the addition of a note 
to the end of the operator precedence page at 
http://uk2.php.net/manual/en/language.operators.php#language.operators.precedence,
 but it seems to me that this is too specific to the ! operator and should be 
generalized.  In fact, I'd completely forgotten that I suggested as much at the 
end of the bug report -- but this hasn't been taken up, so maybe a bunch of you 
want to re-activate the bug report and support my suggestion??

Cheers!

Mike

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