Al wrote:
> I thought the "." had meaning since the manual user notes used it
it means a literal dot, many people assume that glob expressions
use the same syntax as regular expressions but this is not the case.
>
> Definitely, my php is version 4.4.4; it's on a virtual host.
>
> I found the glob file for the GNU C Library and GLOB_ONLYDIR doesn't
> seem to be defined correctly, the file appears to rather old.
>
> I used the numerical value "8196" and it works fine. I'm a little
> reluctant to use the numerical value as I want my code to be generally
> universal. Maybe the numerical value is safer anyhow. What do you think?
you might consider something like this:
if (!defined('GLOB_ONLYDIR'))
define('GLOB_ONLYDIR', 8196);
I doubt that the numeric value will ever change btw.
>
> I can alternatively just filter out the files in a second step.
that seems like a lesser solution.
>
> Al.............
>
>
>
> Jim Lucas wrote:
>> Al wrote:
>>> I can't use flag "GLOB_ONLYDIR" to work on a Linux, php4.4.4. I only
>>> want the dirs.
>>>
>>> This works; sort of:
>>> print_r(glob('../*',)); //It lists all the files AND directories.
>>> Yet it seems to ignore the lack of ".*" and finds xxx.yyy. That's OK,
>>> I can delete the files
>> remember this is linux you are talking about, not windows.
>>
>> A '*' means anything, including a '.'
>>
>>
>>>
>>> This fails:
>>> print_r(glob('../*', GLOB_ONLYDIR));
>> well, double check your php version, because this should be built in
>> whit the version that you are running.
>>
>>>
>>> And I get: "Warning: glob() expects parameter 2 to be long, string
>>> given in foo"
>>>
>>> I can't find anything in the manual or when Googling.
>>>
>>> Anyone can explain this for me?
>>>
>
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