Hi All
I am having a bit of trouble with PHP arrays and would appreciate some help.
I currently have the following piece of code
$count=count($data->legs->leg);
$k=0;
while($k < $count)
{
$legrow[$k]=$data->legs->leg[$k]['legId'].$VM.$data->legs->leg[$k]['depApt'].$VM.$data->legs->leg[$k]['depTime'].$VM.$data->legs->leg[$k]['dstApt'].$VM.$data->legs->leg[$k]['arrTime'].$VM.$data->legs->leg[$k]['equip'].$VM.$data->legs->leg[$k]['fNo'].$VM.$data->legs->leg[$k]['cr'].$VM.$data->legs->leg[$k]['miles'].$VM.$data->legs->leg[$k]['elapsed'].$VM.$data->legs->leg[$k]['meals'].$VM.$data->legs->leg[$k]['smoker'].$VM.$data->legs->leg[$k]['stops'].$VM.$data->legs->leg[$k]['eticket'];
$k++;
}
This works fine extracting the leg attributes from the legs array and
putting the data into a new legrow array delimited by $VM.
I can do a print_r($legrow); and I get the rows displayed correctly. I can
also access any row by using $legrow[n] where n is the key number.
What I want to do is to find a way of indexing the array using the legId
as the key if possible. In other words I want to extract the row where the
legId has a particular value where I do not know the row key.
I have been thinking that this might be possible with an associative array
but my attempts to do this have not worked.
What I have tried is as follows
$count=count($data->legs->leg);
$k=0;
while($k < $count)
{
$legrow["$data->legs->leg[$k]['legId']"]=$data->legs->leg[$k]['depApt'].$VM.$data->legs->leg[$k]['depTime'].$VM.$data->legs->leg[$k]['dstApt'].$VM.$data->legs->leg[$k]['arrTime'].$VM.$data->legs->leg[$k]['equip'].$VM.$data->legs->leg[$k]['fNo'].$VM.$data->legs->leg[$k]['cr'].$VM.$data->legs->leg[$k]['miles'].$VM.$data->legs->leg[$k]['elapsed'].$VM.$data->legs->leg[$k]['meals'].$VM.$data->legs->leg[$k]['smoker'].$VM.$data->legs->leg[$k]['stops'].$VM.$data->legs->leg[$k]['eticket'];
$k++;
}
My thinking is that the $data->legs->leg[$k]['legId'] is the legId and I
might use that as a key. This however does not work.
I would appreciate some guidance on how I might get this to work.
Regards
Richard Luckhurst
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