> -----Original Message-----
> From: Brad Fuller [mailto:[EMAIL PROTECTED]
> Sent: Thursday, March 29, 2007 1:24 PM
> To: 'Tana'; [email protected]
> Subject: RE: [PHP] link on user uploaded pic
>
> > -----Original Message-----
> > From: Tana [mailto:[EMAIL PROTECTED]
> > Sent: Thursday, March 29, 2007 1:02 PM
> > To: [email protected]
> > Subject: [PHP] link on user uploaded pic
> >
> > Hi
> >
> > which is the best way to change this code
> >
> > <img src="images/user_upload/akarmi.jpg">
> >
> > to
> >
> > <a href="images/user_upload/bp_akarmi.jpg"><img
> > src="images/user_upload/akarmi.jpg"></a>
> >
> > in html ?
> >
> >
> > ----------------------------
> > Tana
>
>
> <?php
>
> $imgTag = '<img src="images/user_upload/akarmi.jpg">';
>
> echo preg_replace('/<img src="images\/user_upload\/(.*?)">/', '<a
> href="images/user_upload/bp_$1"><img src="images/user_upload/$1"></a>',
> $imgTag);
>
> ?>
>
> -B
Oops, in that last post part of that code is redundant (forgot about $0 ;)
<?php
$imgTag = '<img src="images/user_upload/akarmi.jpg">';
echo preg_replace('/<img src="images\/user_upload\/(.*?)">/', '<a
href="images/user_upload/bp_$1">$0</a>', $imgTag);
?>
Enjoy,
-B
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