$tempobject *SHOULD* have been an object.

Did you spell it right?

Was $myobject an object in the first place?

Start using var_dump() on all your data and see what's happening.

On Tue, August 7, 2007 4:09 am, Sándor Tamás (GMail) wrote:
> I forgot to tell you that I have to use PHP4.2 because of my web
> provider.
> Anything besides of _clone?
>
> SanTa
>
>   ----- Original Message -----
>   From: Hamza Saglam
>   To: "Sándor Tamás (GMail)"
>   Sent: Tuesday, August 07, 2007 10:49 AM
>   Subject: Re: Object reference into variable?
>
>
>   You may find the following article interesting. It talks about
> object
>   cloning, which I think what you are after...
>
>   http://www.phpfreaks.com/phpmanual/page/language.oop5.cloning.html
>
>
>   Regards,
>   Hamza.
>
>
>   ""Sándor Tamás (GMail)"" <[EMAIL PROTECTED]> wrote in message
>   news:[EMAIL PROTECTED]
>   > Hello,
>   >
>   > I have a question (what a surprise :-) )
>   >
>   > I browsed the archives, but didn't find what I'm looking for.
>   > I have an object instance stored in some variable (like
> $myobject). I want
>   > to save this instance into another variable (like $tempobject). I
> thought,
>   > this will be the way:
>   >  $myobject = new MyObject();
>   >  $tempobject = $myobject;
>   > (or I tried this too:
>   >  $tempobject = &$myobject)
>   >
>   > None of them worked, like I cannot access methods in the object:
>   >  $tempobject->Foo()
>   > gives me an error: calling to method on a non-object variable.
>   >
>   > How can I tell PHP that $tempobject is a class instance of
> MyObject, and
>   > that I can use it's methods?
>   >
>   > Thanks,
>   > SanTa
>
>
>


-- 
Some people have a "gift" link here.
Know what I want?
I want you to buy a CD from some indie artist.
http://cdbaby.com/browse/from/lynch
Yeah, I get a buck. So?

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