Hi,

I've been studying the PHP reference mechanism (with PHP 5.2.1) and I'm unsure if the following behavior is normal.

This code works as expected:

        $a = 2;
        $b = &$a;
        //$c = &$a;
        $c = $b;
        $a = 1;

        echo $c."\n"; // Prints "2" as expected

but this one does not:

        $a = 2;
        $b = &$a;
        $c = &$a;
        $c = $b; // Should overwrite the previous assignment, so $c
                 // should get a copy of $b (and NOT a reference)
        $a = 1;
        
        echo $c."\n"; // I would expect "2", but prints "1"

Could anyone please clarify why this happens?

Regards,
Robert

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