Oops..was overwriting the $result variable...hehe....its fixed.
<?php
$connection = mysql_connect("***","****","****");
if ($connection==false)
{
echo mysql_errno().":".mysql_error()."";
exit;
}
$end = $list + 16;
$query = "SELECT * FROM refer ORDER BY hits desc LIMIT $list, $end";
$result = mysql_db_query ("celebzone", $query);
$num = mysql_num_rows($result);
$j=0;
$i=0;
echo "<table border=0>\n";
for ($j = 0; $j < $num; $j++)
{
echo '<tr>\n';
for ($i = 0; $i <= 1; $i++)
{
@$data = mysql_fetch_array($result);
@$id = $data[id];
@$title = $data[title];
echo "<td>\n";
echo "$title";
echo "</td>\n";
}
echo "</tr>\n";
}
echo "</table>";
echo "<br><br>\n";
?>
Jason Lotito
www.NewbieNetwork.net
PHP Newsletter: http://www.newbienetwork.net/ciao.php
PHP, MySQL, PostgreSQL Tutorials, Code Snippets, and so much more
> -----Original Message-----
> From: McShen [mailto:[EMAIL PROTECTED]]
> Sent: Sunday, June 24, 2001 10:45 AM
> To: [EMAIL PROTECTED]
> Subject: Re: [PHP] ->>coding help
>
>
> Jason, your scripts works prefectly in creating a table. But,
> It only ouputs the first query from the databse. Others are
> not shown. ""Jason Lotito"" <[EMAIL PROTECTED]> wrote in
> message 000f01c0fc67$abfe3a90$72003bd0@genric">news:000f01c0fc67$abfe3a90$72003bd0@genric...
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