>$a = "whatever";
>$b = "abc $a def";
>echo $b;
>
>which results in "abc whatever def" ???
>
>What am I missing?
$b = "abc $a def";
That gets parsed because it's in double-quotes. Since $a is a variable, it
inputs whatever $a is, in this case "Whatever". So it ends up printnig out
"abc whatever def". To fix it, either escape the $a, or use single-quotes.
--Jason
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