On Fri, Dec 12, 2008 at 18:03, Terion Miller <webdev.ter...@gmail.com> wrote:
>
> Well I did some changes and I must be learning because although I have the
> same error I don't have new ones...
> so now the code is like this:
> $sql = "SELECT * FROM `importimages` WHERE `Category` = 'Obits'";
> $result = mysql_query($sql) or die("Error in ".__FILE__.":".__LINE__."
> - ".mysql_error());
> while($object = mysql_fetch_object($result)) {
> foreach($object as $k => $v) {
> echo stripslashes($k).": ".stripslashes($v)."<br />\n";
> }
> }
>
>
> $FileName = $object->Image; <-------This is the line that is telling
> me it is "trying to get the properties of a non-object....
That's because you're calling that as an object using OOP
standards, where I gave you procedural code. To interface with my
code, just call it as:
<?php
// .... other code here....
while($row = mysql_fetch_array($result)) {
echo $row['Image']."<br />\n"; // If `Image` is the column name.
}
// .... code continues....
?>
--
</Daniel P. Brown>
http://www.parasane.net/
daniel.br...@parasane.net || danbr...@php.net
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