On Sun, Jan 11, 2009 at 8:59 AM, MikeP <mpel...@princeton.edu> wrote:
> Hello,
> I am trying yo get THIS:
> where ref_id = '1234'
> from this.
> $where="where ref_id="."'$Reference[$x][ref_id]'";
>
> but i certainly have a quote problem.
>
> Any help?
> Thanks
> Mike
>
>
>
>
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Looks like you're missing the single tics around ref_id. In your
example you'd want one of these:
$where="where ref_id="."'{$Reference[$x]['ref_id']}";
$where="where ref_id="."$Reference[$x]['ref_id'];
$where=sprintf("where ref_id=%d", (int)$Reference[$x]['ref_id']); <--
use this one or else! (sql injection)
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