Ashley Sheridan wrote:
> On Thu, 2009-02-26 at 14:15 -0500, PJ wrote:
>
>> Ashley Sheridan wrote:
>>
>>> On Thu, 2009-02-26 at 13:56 -0500, PJ wrote:
>>>
>>>
>>>> Ashley Sheridan wrote:
>>>>
>>>>
>>>>> On Thu, 2009-02-26 at 13:34 -0500, Darryle Steplight wrote:
>>>>>
>>>>>
>>>>>
>>>>>> Hi PJ,
>>>>>> $db_host = 'biggie';
>>>>>> $db_user = 'root';
>>>>>> $db_pass = 'gu...@#$';
>>>>>> $db_name = 'biblane';
>>>>>>
>>>>>>
>>>>>>
>>>>>> Everyone here is trying to help you and that's cool, but EVERYONE on
>>>>>> this list may not be so nice. The above credentials is definitely the
>>>>>> type of information you want to keep private, unless you don't mind
>>>>>> people potentially accessing your database tables and doing whatever
>>>>>> they like with them.
>>>>>>
>>>>>> I suggest doing something like
>>>>>> $db_host = 'localhost;
>>>>>> $db_user = 'foo';
>>>>>> $db_pass= ''bar;
>>>>>> $db_name =''xxxxxx;
>>>>>>
>>>>>> if you are going to post it on the list.
>>>>>>
>>>>>> On Thu, Feb 26, 2009 at 1:22 PM, PJ <af.gour...@videotron.ca> wrote:
>>>>>>
>>>>>>
>>>>>>
>>>>>>> Ricardo Dias Marques wrote:
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>> Hi PJ,
>>>>>>>>
>>>>>>>> On Thu, Feb 26, 2009 at 17:28, PJ <af.gour...@videotron.ca> wrote:
>>>>>>>>
>>>>>>>>
>>>>>>>>
>>>>>>>>
>>>>>>>>
>>>>>>>>> What is wrond with this file? same identical insert works from console
>>>>>>>>> but not from this file :-(
>>>>>>>>>
>>>>>>>>> [snip]
>>>>>>>>>
>>>>>>>>> <?
>>>>>>>>> //include ("lib/db1.php"); // Connect to database
>>>>>>>>> mysql_connect('biggie', 'user', 'password', 'test');
>>>>>>>>> $sql1 = "INSERT INTO example (name, age) VALUES ('Joe Blow', '69')";
>>>>>>>>> $result1 = mysql_query($sql1,$db);
>>>>>>>>> if (!$result1) {
>>>>>>>>> echo("<P>Error performing 1st query: " .
>>>>>>>>> mysql_error() . "</P>");
>>>>>>>>> exit();
>>>>>>>>> }
>>>>>>>>> ?>
>>>>>>>>>
>>>>>>>>>
>>>>>>>>>
>>>>>>>>>
>>>>>>>> I haven't coded in PHP for a long time, but I think that your problem
>>>>>>>> is in this line:
>>>>>>>>
>>>>>>>> $result1 = mysql_query($sql1,$db);
>>>>>>>>
>>>>>>>> Up to that point, $db (that should point to a database link
>>>>>>>> identifier) is not defined. You probably want to assign the
>>>>>>>> "mysql_connect" result to that $db variable.
>>>>>>>>
>>>>>>>>
>>>>>>>> So, I think that you will solve your problem by changing your
>>>>>>>> "mysql_connect" line FROM the current form:
>>>>>>>>
>>>>>>>> mysql_connect('biggie', 'user', 'password', 'test');
>>>>>>>>
>>>>>>>> .. TO this one:
>>>>>>>>
>>>>>>>> $db = mysql_connect('biggie', 'user', 'password', 'test');
>>>>>>>>
>>>>>>>>
>>>>>>>> Am I right?
>>>>>>>>
>>>>>>>>
>>>>>>>>
>>>>>>> Partly. I had an error in the location of the include. Ashley corrected
>>>>>>> the rest but it only works with the include. Not as whown below
>>>>>>> <?
>>>>>>> //include ("../lib/db1.php"); // Connect to database
>>>>>>>
>>>>>>> $db_host = 'biggie';
>>>>>>> $db_user = 'root';
>>>>>>> $db_pass = 'gu...@#$';
>>>>>>> $db_name = 'biblane';
>>>>>>>
>>>>>>> $db_connect = mysql_connect($db_host, $db_user, $db_pass);
>>>>>>> $db_select = mysql_select_db($db_name, $db_connect);
>>>>>>>
>>>>>>> $sql1 = "INSERT INTO test (name, age) VALUES ('Arnie Shwartz', '75')";
>>>>>>> $result1 = mysql_query($sql1,$db);
>>>>>>> if (!$result1) {
>>>>>>> echo("<P>Error performing 1st query: " .
>>>>>>> mysql_error() . "</P>");
>>>>>>> exit();
>>>>>>> }
>>>>>>> ?>
>>>>>>>
>>>>>>> --
>>>>>>>
>>>>>>> Phil Jourdan --- p...@ptahhotep.com
>>>>>>> http://www.ptahhotep.com
>>>>>>> http://www.chiccantine.com
>>>>>>>
>>>>>>>
>>>>>>> --
>>>>>>> MySQL General Mailing List
>>>>>>> For list archives: http://lists.mysql.com/mysql
>>>>>>> To unsubscribe:
>>>>>>> http://lists.mysql.com/mysql?unsub=dstepli...@gmail.com
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
>>>>> I agree. I wouldn't trust me at all! ;)
>>>>>
>>>>>
>>>>> Ash
>>>>> www.ashleysheridan.co.uk
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>
>>>> Yeah.... very stupid of me...but I found the error: see if you can catch
>>>> it:
>>>> <?
>>>> //include ("../lib/db1.php"); // Connect to database
>>>>
>>>> $db_host = 'xxx';
>>>> $db_user = 'xxx;
>>>> $db_pass = 'xxx';
>>>> $db_name = 'xxx';
>>>>
>>>>
>>>> $db = mysql_connect($db_host, $db_user, $db_pass);
>>>> mysql_select_db($db_name,$db);
>>>>
>>>> $sql1 = "INSERT INTO test (name, age) VALUES ('Arnie Shwartz', '75')";
>>>> $result1 = mysql_query($sql1,$db);
>>>> if (!$result1) {
>>>> echo("<P>Error performing 3st query: " .
>>>> mysql_error() . "</P>");
>>>>
>>>> }
>>>> echo $sql1;
>>>> echo "<br />";
>>>> echo $db_select;
>>>> exit();
>>>> ?>
>>>>
>>>> --
>>>>
>>>> Phil Jourdan --- p...@ptahhotep.com
>>>> http://www.ptahhotep.com
>>>> http://www.chiccantine.com
>>>>
>>>>
>>>>
>>>>
>>> $db_user has not had the string terminated. pray tell was that the
>>> answer you were looking for?!
>>>
>>>
>>> Ash
>>> www.ashleysheridan.co.uk
>>>
>>>
>>>
>>>
>> No. Damn those typos!
>>
>> What seems to have made it work is just
>>
>> $db = mysql_connect($db_host, $db_user, $db_pass);
>> mysql_select_db($db_name,$db);
>>
>> not using mysql_select in a string....
>> but would you use it in a string? how & why?
>>
>> --
>>
>> Phil Jourdan --- p...@ptahhotep.com
>> http://www.ptahhotep.com
>> http://www.chiccantine.com
>>
>>
>>
> Yeah, you'd typo'd on the variable name. Also, the $ sign doesn't
> actually denote a string, but a scaler variable, which can be any type,
> complex or simple.
>
I type too fast and am too speedy... :-)
I'll have to look up about the variables.
Thanks & good night. 'Til the morrow.
--
Phil Jourdan --- p...@ptahhotep.com
http://www.ptahhotep.com
http://www.chiccantine.com
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