Shawn McKenzie wrote:
> Daevid Vincent wrote:
> > I'm trying to remove ["menu"] == 'Login' from the array, but despite
> "finding" the element, it never removes.
>> isn't that what the & reference stuff is for?
>
> Yes, but foreach can't modify an array unless you use a reference in the
> foreach also. Try this:
>
> foreach($menuItems as &$value)
>
>
>> menuItem::removeMenuItems($navArray['dart'], array('Login', 'Lost
>> Password'));
>>
>>
>> public static final function removeMenuItems(&$menuItems, $removeArray)
>> {
>> foreach($menuItems as $value)
>> {
>> if (is_array($value->children))
>> menuItem::removeMenuItems(&$value->children,
>> $removeArray);
>> else
>> {
>> //echo "*** CHECKING ".$value->menu." against
>> ".implode(',',$removeArray)." ***";
>> if (in_array($value->menu, $removeArray))
>> {
>> //echo "*** REMOVING ".$value->menu."
>> ***";
>> unset($value);
>> }
>> }
>> }
>> }
>>
>
>
Also, I'm not sure what happens here:
if (is_array($value->children))
menuItem::removeMenuItems(&$value->children, $removeArray);
else
{
Your function defines that var as a reference so you don't have to use a
reference in the call. Don't know if it does anything but throw a
deprecated notice though.
--
Thanks!
-Shawn
http://www.spidean.com
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
