haliphax wrote:
> On Fri, Mar 27, 2009 at 9:40 AM, Shawn McKenzie <[email protected]> wrote:
>> I'm normally OK with regex, especially if I fiddle with it long enough,
>> however I have fiddled with this one so long that I'm either totally
>> missing it or it's something simple. Does it have anything to do with
>> the backref, or the fact that the value of the backref has a $? I have:
>>
>> $out = '
>> {$sites}
>> <tr>
>> <td>
>> {Site.id}
>> </td>
>> </tr>
>> {/$sites}';
>>
>> And I want to capture the first {$tag}, everything in between and the
>> last {$/tag}. I have tried several things and here is my current regex
>> that looks like it should work, but doesn't:
>>
>> preg_match_all('|{\$([^}]+)}(.+)({/\1})|Us', $out, $matches);
>
> Shawn,
>
> First thing I see--your first capture group doesn't include the $, and
> so your final capture group will always fail given your current $out
> (because it's looking for {/sites} instead of {/$sites}). Also, your
> {} are outside of your capture group in \1, but inside in \3. Here's
> what I came up with:
>
> $out = '
> {$sites}
> <tr>
> <td>
> {Site.id}
> </td>
> </tr>
> {/$sites}';
> $matches = array();
> preg_match_all('#{(\$[^}]+)}(.*?){(/\1)}#s', $out, $matches);
> print_r($matches);
>
> Produces this:
>
> Array
> (
> [0] => Array
> (
> [0] => {$sites}
> <tr>
> <td>
> {Site.id}
> </td>
> </tr>
> {/$sites}
> )
>
> [1] => Array
> (
> [0] => $sites
> )
>
> [2] => Array
> (
> [0] =>
> <tr>
> <td>
> {Site.id}
> </td>
> </tr>
>
> )
>
> [3] => Array
> (
> [0] => /$sites
> )
>
> )
>
> Keep in mind, I had to view the page source in order to see the HTML
> tags, but it showed me everything I expected to see.
>
> HTH,
>
Yes, thank you. I was fiddling before I got your post and I came up
with roughly the same.
preg_match_all('|{(\$[^}]+)}(.+){(/\1)}|Us', $out, $matches);
--
Thanks!
-Shawn
http://www.spidean.com
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