On 4/28/09 11:23 AM, "Jan G.B." <ro0ot.w...@googlemail.com> wrote:
2009/4/28 Miller, Terion <tmil...@springfi.gannett.com>:
> Can someone help with how to make this work, trying to get the number of
> rows but am getting the "trying to get property of non-object"
>
> Code-----------------
>
> $query = "select blah, blah, blah from table where ".$type." like
> '%".$name."%'";
>
> $result = mysql_query($query);
>
> $num_results = $result->num_rows; <---------------this is the line with
> error
>
Hi Terion,
you're mixing normal mysql_* with mysqli. Mysqli is object oriented
and the mormalö mysql_ functions aren't - thei're procedural.
So you can do it either like
$result = mysql_query("SELECT 1");
$num = mysql_num_rows($result);
Or in OOP
$res = $mysqlObj->query("SELECT 1"); // $mysqlObj should be
initialized first ;) hint: new mysqli()
$num = $res->num_rows();
Check ot this URL: http://php.net/mysqli
byebye
Hmm, well I did some looking at other codes etc and some tweaking but still get
two problems:
Changed my code to try and use an array because that has worked before when I
have run into the object error, but I still get this error:
Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result
resource
Warning: mysql_num_rows(): supplied argument is not a valid MySQL result
resource
Here is my code now:
$query = "select name, age, warrant, bond, wnumber, crime FROM warrants
where ".$warranttype." = ".$warranttype." OR ".$searchname." = ".$searchname."
"; $result = mysql_query($query); $row = mysql_fetch_assoc($result);
$num_results = mysql_num_rows ($result);
Should this post of gone on the Db list maybe?
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