m a r k u s wrote:
> Hi all,
> I see that from PHP 5.3.0 ereg_replace() function is deprecated and
> throws a warning.
> I would like to use the preg_replace() function as an alternative of
> ereg_replace() function but... can't undestand the "\n#[^\n]*\n"
> expression.
> $sql = ereg_replace("\n#[^\n]*\n", "", $sql);
> Any help for tranlation or alternative ?
> Thanks
> -- 
> m a r k u s

Here's a good regex tutorial:  http://www.regular-expressions.info/

But to answer your question, \n#[^\n]*\n means the match must:

start with a newline(\n) followed by a pound sign (#) followed by 0 or
more characters (*) that are not a newline(^\n) all the way up to
another newline (\n).

To translate to preg I think all you need to do is give it delimiters,
but that may not be necessary, not sure. "|\n#[^\n]*\n|"


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