The "private" keyword was added in PHP 5. PHP 4 doesn't have visibility
identifiers. In PHP 4 you have to use "var", which is then always public.
Or you could just use PHP 5 instead of a dead language. :-)
Ashley Sheridan wrote:
Is there any reason why this shouldn't work correctly on a server
running PHP 4.4.7:
private $foo = 'bar';
I would at the very least expect to see the 'wtf' printed out. I've got
a whole class I've written that works fine in PHP 5, but on PHP 4
server, it does nothing with even this simple example.
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