strtotime would be a neater way of solving the problem...
ie (untested):
$n = 0;
while ($n <= 9)
{
$date = "d".$n;
$$date = date("Y-m-d", strtotime("+ $n days")
$n++;
}
If you are just enquiring about the maths though, I'm not sure!
-----Original Message-----
From: Korgan [mailto:[email protected]]
Sent: 15 September 2009 16:32
To: [email protected]
Subject: [PHP] Problem with date
Hi,
I have a problem with date function.
$gen_pos = mktime(0,0,1,10,25,2009);
$d1 = date("Y-m-d", $gen_pos); // 2009-10-25
$d2 = date("Y-m-d", $gen_pos + (1*24*60*60)); // 2009-10-25
$d3 = date("Y-m-d", $gen_pos + (2*24*60*60)); // 2009-10-26
$d4 = date("Y-m-d", $gen_pos + (3*24*60*60)); // 2009-10-27
$d5 = date("Y-m-d", $gen_pos + (4*24*60*60));
$d6 = date("Y-m-d", $gen_pos + (5*24*60*60));
$d7 = date("Y-m-d", $gen_pos + (6*24*60*60));
$d8 = date("Y-m-d", $gen_pos + (7*24*60*60));
line 2 and line 3 return same date,its wrong ... it should be 2009-10-25
, 2009-10-26 ? :)
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php