Hello,
I just spent way, way to much time trying to debug code due to a misnamed
element. Here is a simplified example of the problem I dealt with.
$test = "SELECT * FROM `Materials` WHERE `Part_Number` = '125664'";
$result = mysql_query($test,$handle);
if(!$result)
{
die('Error: ' . mysql_error());
}
$row = mysql_fetch_array($result);
echo $row['Number'];
After retyping the code 3 or 4 times over the course of the morning, I finally
found where the problem was. The problem is that the database field is called
'Part_Number', not 'Number'. The field 'Number' does not exist in the
database. I am very surprised that I didn't even get a warning that there
might be a problem with the statement. All I saw is that nothing was being
returned via the echo command.
There really must be a stricter error checking that is turned on somewhere,
isn't there?
Thanks for your help.
Tim
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