You can name the pseudo-column by doing "select AVG(age) as avgage from ..."
and then accessing it as "avgage".

- Tim
  http://www.phptemplates.org

----- Original Message -----
From: "Jeff Lewis" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, July 10, 2001 11:27 AM
Subject: [PHP] Average of column...


> I am trying to obtain the average age for a few teams in my database.
> $age_result = mysql_query("select AVG(age) FROM bat_rost WHERE ownerID =
> '$teamID'");
> while(($row = mysql_fetch_object($age_result))){
>   $age=$row->age;
> echo "Average age - ".$teamID.$age;}
>
> How can I get the average age from this?



-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]

Reply via email to