Yes, what Ashley said is correct. Also, if you want to avoid writing
$perm several times in the if, or if you have a lot of permissions you
can do:

if (in_array($perm, array(11, 22)))

And you can put in that array all the permissions you need to.



On Fri, Dec 18, 2009 at 3:47 PM, Ashley Sheridan
<a...@ashleysheridan.co.uk> wrote:
> On Fri, 2009-12-18 at 10:21 -0800, Allen McCabe wrote:
>> In a nutshell:
>> Will this work?
>> if ($perm == (11 || 12))
>> Explanation:
>> I am laying the groundwork for a photo viewing system with a private and
>> public mode, and additionally if an admin is logged in, there is an
>> additional level of permission. I came up with a number system to make it
>> easier (and is calcualted by a class) so now, instead of checking against
>> the $mode variable, if the user is logged in, and then what their user level
>> is if they are logged in, I just check against some numbers (the class
>> evaluates all those conditions and assigns the appropriate number a single
>> permission variable, $perm.
> That equates to if($perm == true) as 11 in this case translates to true
> (being a positive integer) The code never needs to figure out the ||
> part, as the first part is true.
> I think what you'd want to do is possibly:
> if($perm == 11 || $perm == 12)
> Thanks,
> Ash
> http://www.ashleysheridan.co.uk

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