Hello Shawn,

Hm... isn't it expected behavior? Since you haven't defined a
$a['test'] item, PHP throws a notice... or I'm wrong?
-- 
With best regards from Ukraine,
Andre
Skype: Francophile; Wlm&MSN: arthaelon @ yandex.ru; Jabber: arthaelon @ 
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Yahoo! messenger: andre.polykanine; ICQ: 191749952
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----- Original message -----
From: Shawn McKenzie <nos...@mckenzies.net>
To: php-general@lists.php.net <php-general@lists.php.net>
Date: Thursday, April 8, 2010, 8:36:21 PM
Subject: [PHP] No notices for undefined index

So the first two print statements generate NO notices, while the second
obviously generates:

Notice: Undefined offset:  1 in /home/shawn/www/test.php on line 11

Notice: Undefined index:  test in /home/shawn/www/test.php on line 12

This sucks.  A bug???

error_reporting(E_ALL);
ini_set('display_errors', '1');


$a = 5;
print $a[1];
print $a['test'];

$a = array();
print $a[1];
print $a['test'];

-- 
Thanks!
-Shawn
http://www.spidean.com

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