On Thu, Apr 22, 2010 at 10:12 AM, Stephen <stephe...@rogers.com> wrote:

> 1,252,398 DIV 30 = 41,746 groups of 30.
> 1,252,398 MOD 30 = 18 items in last group
Well, the only problem with going that route, is the one group is not
equally sized to the others.  18 is ok for a group in this instance, but if
it was a remainder of only 1 or 2, there would be an issue.  Which is where
I come to looking for a the right method to break it equally.

-Dan Joseph

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