hello list,

I'm trying to manage a image resouce inside a method, but

In detail, that's some code snippets:

the class and the method:


class canvas{

    function makeImage($imageWidth = 850){

        $im = imagecreate(110, 20) or die("Cannot Initialize new GD
image stream");
        $background_color = imagecolorallocate($im, 0, 0, 0);
        $text_color = imagecolorallocate($im, 233, 14, 91);
        imagestring($im, 1, 5, 5,  "A Simple Text String", $text_color);
        return $im;


... than my test.php file:

header("Content-type: image/png");
$c = new canvas();

the result in the browser isn't the image itself, but an error that
sounds like: (I traslate the message from italian):
"Image can't be displayed because contains some errors"

but... if I comment out the "header" line, I get this:

‰PNG  ��� IHDR���n������V,š���PLTE���é[an÷���fIDAT•c` `fxÄÀÃ`Ç
ÀçÀä²41ƒ‚€˜Ë–Ý’À...@੤;{á0— œi

...sounds like a png image, isn't it? but It doesn't :-/

The code in the method is very simple, is the same of the php manual
page of "imagecreate" function, and I think the resource is correctly
managed, 'cause if I write this:

$c = new palinsestoCanvas(3);

I get: "Warning: imagepng(): supplied argument is not a valid Image

.. so I think $c->makeImage()) returns successfully the resource.. but I
still didnt see my image..

Any help is appreciated, thanks


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