> $categorys = array('home', 'services', 'gallery', 'about_us', 'contact_us',
> 'testimonials');
If(in_array($_GET['page'], $categories))
{
echo '<li><a href=index.php?page='.$_GET['page'].'>'.str_replace("_","
",$_GET['page']).'</a></li>';
}else{
echo '<li>'.str_replace("_"," ",$_GET['page']).'</li>';
}
I normally never write someones code for them but you are just not getting it.
The above code works use it.
> $deadlink = $_GET['page']; <-- useless
>
>
>
On Jan 13, 2011, at 12:45 PM, Nathan Rixham <nrix...@gmail.com> wrote:
> David McGlone wrote:
>> Hi everyone,
>> I think the subject is right, or somewhere close. Anyway I am trying to
>> perform a little trickery here with links. In the following code you can see
>> where I am trying to replace the link on the current page so it's not a link
>> when on that page. I think I got the general idea of what I need to do as
>> you can see in the code I just don't know how to accomplish it, if it's
>> possible.
>> $categorys = array('home', 'services', 'gallery', 'about_us', 'contact_us',
>> 'testimonials');
>> foreach($categorys as $category){
>> $deadlink = $_GET['page'];
>> if ($deadlink == 'page') {
>
> for a short answer, all you need to do is change the above line to:
>
> if($deadlink == $category)
>
> and as a slightly colourful variant:
>
> $categorys = array('home', 'services', 'gallery', 'about_us', 'contact_us',
> 'testimonials');
> foreach($categorys as $category){
> $temp = str_replace("_", " ", $category);
> $_GET['page'] != $category && $temp = '<a href="index.php?page='. $category
> .'">'.$replace.'</a>';
> echo "<li>{$temp}</li>" . PHP_EOL;
> }
>
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