15.02.2011 00:24, Paul M Foster yazmış:
On Mon, Feb 14, 2011 at 05:15:11PM -0500, Floyd Resler wrote:

On Feb 14, 2011, at 4:18 PM, Paul M Foster wrote:

On Mon, Feb 14, 2011 at 03:35:02PM -0400, Paul Halliday wrote:

I have 2 buttons on a page:

if (isset($_POST['botton1'])) {dothing1();} if
(isset($_POST['button2'])) {dothing2();}

They both work as intended when I click on them. If however I click
within a text box and hit enter, they both fire.

Is there a way to stop this?
Check your code. My experience has been that forms with multiple
submits will fire the *first* submit in the form when you hit Enter
in a text field or whatever. I just tested this and found it to be

Now, I'm doing this in Firefox on Linux. I suppose there could be
differences among browsers, but I suspect that the specs for HTML
mandate the behavior I describe.


If you don't mind using a little JavaScript you can test for which
button should fire when enter is pressed.  How I would do it is to
first add a hidden field and call it "buttonClicked".  Now, in the
text field where you would like a button to fire if enter is pressed,
at this to the tag: onkeyup="checkKey(this,event)".  For the
JavaScript portion of it, do this:
Yeah, but you don't even have to go that far. Just put a print_r($_POST)
at the beginning of the file, and you'll see which button gets pressed.
It will show up in the POST array.


this could also work;
function send ( selectedtype )
document.formname.postingvalue.value = selectedtype ;
document.formname.submit() ;
<form name=formname>
<input type="hidden" name="postingvalue" />
<a href="javascript:send('1')">Button 1</a></td>
<a href="javascript:send('2')">Button 2</a></td>
<a href="javascript:send('3')">Button 3</a></td>
{ code here } elseif ($_POST['postingvalue']=="1")
{ code 2 here } bla bla

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