On 11-02-16 11:37 AM, דניאל דנון wrote:
I have a table called "images" with 4 columns - `image_id`, `item_name`,
(Where image_id is UNIQUE and AUTO-INCREMENT).
Sometimes, there might be many items with the same name (but not with the
I want to make sure that each "item name" has at most 3 images (and
therefore I need to delete the rest).
The problem is that I want to keep the images with the most views.
I've tried to look for efficient solutions either in MySQL or in PHP, but
they are mostly very resource-intensive,
Such as selecting all different names in PHP (using GROUP BY), then, for
each name, doing DELETE FROM images WHERE item_name = 'ITEM-NAME-HERE' ORDER
BY image_views ASC LIMIT (here some sub-query with count on how many rows
have the name ITEM-NAME-HERE minus 3).
I'd be glad if anyone could help me or point me to the right direction.
I'd use a cron job to manage the purging process... and off the top of
my head I'd probably go the following route:
Get the list of images with more than 3 of the same name:
SELECT item_name, SUM( 1 ) AS total FROM images HAVING total > 3;
Get the 3 best images for each image returned above:
SELECT image_id FROM images WHERE image_name = '[[NAME]]' ORDER BY
(Make sure to quote your criteria properly in the above-- this is pseudo
Now delete the laggards using the ID we just retrieved:
DELETE FROM images WHERE image_id NOT IN ([[ID_LIST]]).
That should get you to a decent solution.
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