On Thursday, 31 March 2011 at 15:45, Nicholas Cooper wrote:
Good day,
> I have three arrays A, B and C. Anyone of them might not have the 'id' key
> set which will give the Notice "Undefined index: id".
> I just wanted to know what the correct approach to this problem would be;
> without making the code overly complicated to read by introducing a number
> of "if isset" statements.
> if ($arrayA['id'] == $arrayB['id'] || $arrayC['id'] == $arrayB['id']) {
> }
> I have notices switched off, but I want to know the right way to do this.
>  There's probably a number of different right ways to solve this, how would
> you do it?

This is how I handle this...

// Define this function somewhere global
function ifsetor($array, $key, $default = null)
return (isset($array[$key]) ? $array[$key] : $default);

if (ifsetor($arrayA, 'id') == ifsetor($arrayB, 'id') || ifsetor($arrayC, 'id') 
== ifsetor($arrayB, 'id'))...

If you need to avoid a match if neither $arrayA nor $arrayB have an id you 
simply pass a different default for each one.


Stuart Dallas
3ft9 Ltd


PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

Reply via email to