Alex <niks...@gmail.com> wrote:
>If you were to use the proper object form of it, you'd spot the >mistake, as it will tell you that you are trying to perform an action >on a non-object. > >It might be a bug, or the developers might not have cared figuring that >if you threw it in an if(!...) it would validate as false anyways. But >it.might be a bug or an oversight. It might actually be falling through >some ifs and returning the result that was instantiated as null, I >dunno... > >Sent from my Verizon Wireless 4GLTE smartphone > >----- Reply message ----- >From: "James Colannino" <ja...@colannino.org> >To: <php-general@lists.php.net> >Subject: [PHP] mysqli_query() returns NULL? >Date: Fri, Jun 17, 2011 4:40 pm > > >Hey everyone, > >After reading the documentation for mysqli_query(), I was lead to >believe that on any error it would return false. However, through a >stupid mistake, I discovered that when I specify an invalid value for >the database link identifier (in my case, I accidentally passed an >integer), instead of false I get a return value of NULL. Does anyone >know why? > >Thanks! > >James > >-- >PHP General Mailing List (http://www.php.net/) >To unsubscribe, visit: http://www.php.net/unsub.php You'll only get an error if there was an error with the query. A query that has no result is still a valid query, so won't return an error. It's quite common to check the value of mysql_num_rows() before trying to use the results of the query. Ashley Sheridan http://www.ashleysheridan.co.uk -- Sent from my Android phone with K-9 Mail. Please excuse my brevity. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
