On 9/08/2011, at 8:20 AM, Andre Polykanine wrote:
> Hi everyone,
>
> As we all know, count() returns 1 if the variable
> is not an array.
> Question is: why in the world does it this? If a variable is *notA* an array,
> it contains *zero* array elements.
> You can answer: "but no, man, you can say
> $x="world";
> $y=$x{3}; // $y="l"
>
> so the variable is treated or can be treated as an array".
> Well. If strings are treated like arrays, why count($x) doesn't return 5
> instead of 1?
> Just asking.
>
> --
> With best regards from Ukraine,
> Andre
I'm assuming it has to do with the value, if not an array or object, being cast
as an array. Thus, non-false equivalent values get cast into an array of size 1:
<?php
var_dump((array)1);
var_dump((array)null);
// Output
array(1) {
[0]=>
int(1)
}
array(0) {
}
---
Simon Welsh
Admin of http://simon.geek.nz/
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