Quoting Benjamin Coddington <bcodd...@uvm.edu>:
Are there any assurances that function local variables are protected
from code calling the function?
For example, I would like to provide some cryptographic functions such as
function org_secure_string($string) {
$org_key = "a very random key";
return hash($string, $key);
}
function org_reveal_string($hash) {
$org_key = "a very random key";
return unhash($hash, $key);
}
I'd like to protect $org_key from any code following or using these
functions. I've not yet found a way that it can be revealed, but I
wonder if anyone here can give me a definitive answer whether or not
it is possible.
It's called the scope of the variable. See
http://us3.php.net/manual/en/language.variables.scope.php
Variables defined in a function are only available to the function
where they are defined.
Ken
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
