Hi all,
I have a problem with PHP passthru() blocking when it is supposed to start a
daemon and return.
I have a Node.js daemon with a bash script wrapper around it. Users can call
this bash script directly, but it is also used by our deployment system. Our
deployment system uses Phing, and Phing uses `exec()` and `passthru()`
internally to cann external programs.
The bash script wrapper around my Node.js uses a bit of process replacement
because my Node.js server can't directly log to syslog. Normally I'd start
Node.js like this:
forever -l app.log app.js
But because I want it to log to syslog, I put this in the bash script:
forever -l >(logger) app.js
The `logger` process replacement creates a file descriptor into syslog like
/dev/fd/63 whose path is passed to the forever command as the logfile to use.
This works great when I start the daemon using the bash script directly, but
when the bash script is executed using PHP passthru() or exec() then these
calls will block. If I use a regular logfile instead of the process
replacement then both passthru() and exec() work just fine, starting the
daemon in the background.
I have created a complete working example (using a simple PHP daemon instead
of Node.js) on Github's Gist: https://gist.github.com/1977896 (needs PHP 5.3.6+)
Why does the passthru() call block on the process replacement? And is there
anything I can do to work around it?
Kind regards,
--
Sander Marechal
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