Not a solution but some bricks to build it:
if (isset ($var)){
...
}else{
...
}
isset test if $var is set, but if you once assigned the var even an empty
value, this will be true (e.g. after a $var=""; statment, isset will return
true).
You can unset $var with unset($var);
Furthermore if $var contains 0 or "" both will go into the else statement if
you write
if ($var != ""){
}else{
}
thats because for php "" == 0
But you can use ===
0 === "" will return false (because 0 is an integer but "" a string) while
0 == "" will return true (because 0 and "" are equal to false)
but I think you'll have to combine it because
0 === "somestring" will also return false
hope you can use those informations
Stefan Rusterholz, [EMAIL PROTECTED]
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Stefan Rusterholz
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----- Original Message -----
From: "Saquib Farooq" <[EMAIL PROTECTED]>
To: "Dave Freeman" <[EMAIL PROTECTED]>
Cc: "php" <[EMAIL PROTECTED]>
Sent: Saturday, July 21, 2001 11:50 AM
Subject: Re: [PHP] testing if var is empty
> On Sat, 21 Jul 2001, Dave Freeman wrote:
>
> > On 21 Jul 01, at 12:07, Justin French wrote:
> >
> > > I'm a semi-newbie, and if I want to check if a variable is set, or
> > > contains something, i've been doing it like this:
> > >
> > > if($var != "") { ... }
> >
> > if ($var)
> > {
> > // $var has been set
> > } else {
> > // $var has not been set
> > }
> >
> >
> > will do what you want.
> >
> > CYA, Dave
> what if the var is set to zero i.e. false. the control will go in
> the else part if it is not zero ( not false) it will go in the if control.
>
>
>
>
>
>
>
> >
> >
> > -----------------------------------------------------------------------
> > Outback Queensland Internet - Longreach, Outback Queensland - Australia
> > http://www.outbackqld.net.au mailto:[EMAIL PROTECTED]
> > -----------------------------------------------------------------------
> >
> >
>
> --
> Saquib Farooq
> @
> Systems @ SDNPK
> Islamabad
>
>
> --
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