On Fri, Jan 18, 2013 at 9:43 AM, Daniel Brown <danbr...@php.net> wrote:
> On Fri, Jan 18, 2013 at 10:33 AM, KISE <wowk...@gmail.com> wrote:
>> Paul Dragoonis,
>> Actually it wont work i did tried it before, if the dir end with / it will
>> list the directories inside the path you gave it and if it doesn't have any
>> directories it will return false since there is no directories to return.
>> you have to take out the last / and then remove the directory in question
>> and list the files in the parent directory and check if the dir exists
>> otherwise it will return false, i spent 3hrs yesterday thinking why its
>> returning false even though the directory exists.
>     The discussion is now getting more into the general coding realm
> than internals, so let's move it over there in case anyone wants to
> mention something like:
> function ftp_dir_exists($conn, $currentDir) {
>         $currentDir = (substr($currentDir,-1,1) == '/') ?
> substr($currentDir,0,-1) : $currentDir;
>         $list  = ftp_nlist($conn, '-dF '. $currentDir);
>         return in_array($currentDir, $list);
> }

Haven't played with ftp functions at all, but wondering what if you
gave it dirname($currentDir) instead of $currentDir? (Still have to do
the trailing '/'-ectomy)

   $list = ftp_nlist($conn, dirname($currentDir));

untested, just a thought.

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