# Re: [PHP] Finding an Address

```well, not exactly.
But I can help you (so can others) to go through code flow (it will
probably be tedious)```
```
you have a position you start and a certain distance from that point (in a
circle)
>From thereon you substract start(x,y) from dest(x,y) by substracting x from
x and y from y the diffence is the amount of degrees between the two points

so for example you are currently at long: 75, lat: 31 and you want to know
some point 6.9 miles away.
you start by adding 0 to 75 and 0.1 to 31 you then have one point (both are
degrees and one degree is roughly 69 miles) you can also do the opposite,
add 0.1 to 75 and 0 to 31, you can also add 0.05 to both (again totaling
0.1), mind though the values that total 0.1 are absolute, even though the
long/lat may be negative.

The point is that the values added are combined the distance you want to
measure against.
>From thereon you can determine if there is an address at the location
(using reverse geo-coding).
when increasing the number you add, you measure further and further
you'll have to do that all arround the point you started from

http://www.nationalatlas.gov/articles/mapping/a_latlong.html

HTH

Kind regards/met vriendelijke groet,

Serge Fonville

http://www.sergefonville.nl

Convince Microsoft!
They need to add TRUNCATE PARTITION in SQL Server
https://connect.microsoft.com/SQLServer/feedback/details/417926/truncate-partition-of-partitioned-table

> Serge,
>         That is precisely what I want!  Any ideas on how to accomplish
> that?
>
> Thanks!
> Floyd
>
>
> On Feb 28, 2013, at 2:52 PM, Serge Fonville <serge.fonvi...@gmail.com>
> wrote:
>
> > HI,
> >
> > It seems like you want something according to the following
> >
> > you know your start long/lat
> > you can determine the long/lat arround it
> > for every of those you determine the route.
> > if you follow that route you know the house you find
> > otherwise you can use an increasing circle and if it finds an address on
> the location, you may be able to determine which of the points in the
> circles (which increase in size) is closest.
> >
> > Does that match what you want?
> > If not, could you further elaborate what you want exactly?
> >
> > Kind regards/met vriendelijke groet,
> >
> > Serge Fonville
> >
> > http://www.sergefonville.nl
> >
> > Convince Microsoft!
> > They need to add TRUNCATE PARTITION in SQL Server
> >
> https://connect.microsoft.com/SQLServer/feedback/details/417926/truncate-partition-of-partitioned-table
> >
> >
> > 2013/2/28 Floyd Resler <fres...@adex-intl.com>
> >
> >
> >
> > On Feb 28, 2013, at 1:04 PM, kenrb...@rbnsn.com wrote:
> >
> > > On 28.02.2013 12:36, Floyd Resler wrote:
> > >> I have a project where my client would like to find the nearest
> > >> street address from where he current is.  Getting the longitude and
> > >> latitude is easy enough but I'm having a hard time finding out how to
> > >> get the nearest house.  I have found a lot of solutions for addresses
> > >> maintained in a database but these addresses won't be in a database.
> > >> I thought about just querying Google for each longitude and latitude
> > >> within in a small circle but my math skills are nowhere near good
> > >> enough to accomplish that.  Anyone have any ideas?
> > >>
> > >> Thanks!
> > >> Floyd
> > >
> > >
> > > Have you tried Google Maps reverse geocoding?
> > >
> > > Ken
> > >
> > That's what I'm doing but I need to find the closest say five houses to
> the current latitude and longitude coordinates.
> >
> > Thanks!
> > Floyd
> >
> >
>
>
```