2013/3/16 Andrew Ballard <aball...@gmail.com>

> I suppose one could try something like this:
> if (is_string($val) && $val === (string)(int)$val) ....
> If $val is an integer masquerading as a string, it should be identical to
> the original string when cast back to a string, shouldn't it? (I can't try
> it right now.)

It is semantically equivalent to

$val == (int) $val

and as far as I remember (I didn't read everything completely) this were
mentioned. I didn't read, whether or not, it was accepted as solution ;)

> Andrew


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