On Aug 9, 2013, at 8:00 AM, Karl-Arne Gjersøyen <karlar...@gmail.com> wrote:
> 1) query
> foreach($varenr_inn_pa_lager as $vnr){
> include('../../tilkobling.php');
> $sql = "SELECT * FROM exan,dynamit WHERE varenr = '$vnr' LIMIT
> 1";
> $resultat = mysql_query($sql, $tilkobling) or
> die(mysql_error());
>
> 2) Result:
> Column 'varenr' in where clause is ambiguous
>
> 3) Tables in MySQL database
>
> mysql> SELECT * FROM exan;
> +------------+-------------+-------+----------+----------+-------------+
> | leverandor | valgt_lager | un_nr | varenavn | varenr | kg_pa_lager |
> +------------+-------------+-------+----------+----------+-------------+
>
> mysql> SELECT * FROM dynamit;
> +------------+-------------+---------------+--------+-------+---------------------+------------+-------------+
> | leverandor | valgt_lager | type | dim_mm | un_nr |
> varenavn | varenr | kg_pa_lager |
> +------------+-------------+---------------+--------+-------+---------------------+------------+-------------+
>
> 4) My question:
> What means with "ambiguous" here?
>
> Thanks.
> Karl
Your field "varenr" is in both tables you are joining. Therefore, MySQL
doesn't know which table it should use the field from. So, you need to qualify
it by putting the table name in front of the field. Such as:
SELECT * FROM exan,dynamit WHERE exan.varenr='$vnr' LIMIT 1
Take care,
Floyd
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
