Thank you. That worked and I'm sure will have made it work a lot
faster later on when there is a lot of data in the database.
Jeff Oien

> On Sat, 4 Aug 2001 12:40:42 -0500, Jeff Oien ([EMAIL PROTECTED]) 
> wrote:
> >After a sign up page I want to check if someone is already entered
> >into a database. The First Name, Last Name and Address all have
> >to match exactly in order for it to be considered a duplicate. 
> >However
> >this isn't doing what I want. I get the Error produced if the 
> >Address matches 
> >but the name doesn't. Not sure what I'm doing wrong. Thanks.
> >Jeff Oien 
> 
> you're going about this the wrong way.
> try it like this:
> 
> $result=mysql_query("select * from table where first='$first' and 
> last='$last' and address='$address'");
> 
> if(mysql_num_rows($result)){
>   // error code
> }
> 
> you want to keep the result sets that mysql gives back as small as 
> possible because they take up tons of resources.
> 
> >while ($row = mysql_fetch_array($result)) {
> >     $First_Name = $row['First_Name'];
> >     $Last_Name = $row['Last_Name'];
> >     $Address = $row['Address'];
> >     
> >     if (($M_First_Name || $F_First_Name == $First_Name) && 
> >     ($M_Last_Name || $F_Last_Name == $Last_Name) 
> >     && ($Address1 == $Address)) {
> >     echo "
> >     <html><head><title>Error</title>        </head>
> >     <body bgcolor=\"#FFFFFF\" text=\"#000000\" link=\"#0000ff\" 
> >vlink=\"#660099\">
> >     <h3>Error</h3>
> >etc...
> >
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> 
> 
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