[PHP] if statement and imageline()

[Hugh Danaher]

help,

I am trying to set up a .jpg file to graph the earnings per year of a company.  I can 
generate a log-normal graph, can get it to display the earnings per year as circles on 
the graph, but I can't get the  " if () " statement to work.  I know I am setting two 
of the variables in the if statement after the if statement executes once, but these 
variables won't be used until after the " for () " loops once, and therefore should be 
available for use in " imageline() " on the second loop (where $year>$startyear).  
Somehow, I think my logic is correct but it mustn't be so.


$startyear=1996;
$chart_start_year=1992;
for ($year=$startyear;$year<=$startyear+7;$year++)
     {
     $x=(($year-$chart_start_year)*20)+20;
     $y=420-log(${"earnings_".$year})*75;
     if ($year>$startyear)
          {
          imageline($image,$first_x,$first_y,$x,$y,$blue);
          }
     $first_x=$x;
     $first_y=$y;
     imagettftext($image,9,0,$x_distance-4,$y_distance+3,$blue,$font2,"m");
     }