The hard drive may be showing you the file's ALLOCATED size, which will be
an "even" number.
What does:
<?php echo filesize('/path/to/new/file/');?>
give you?
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----- Original Message -----
From: Ben-Nes Michael <[EMAIL PROTECTED]>
To: Richard Lynch <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Thursday, August 23, 2001 3:03 AM
Subject: Re: [PHP] Re: imagemagick and file size
> Hi Again
>
> Strange but same command to return the $data or to save it to the HD
> returned diffrent data length
>
> when the data returend to $data
> strlen($data) -> output 4075
> while the saved file is -> 4252
>
> Any one know why there is diffrence ?
>
>
> ----- Original Message -----
> From: "Richard Lynch" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Thursday, August 23, 2001 2:01 AM
> Subject: [PHP] Re: imagemagick and file size
>
>
> > > function example() {
> > > $convert = "cat $userfile | /usr/X11R6/bin/convert - $type:-";
> > > return `$convert`;
> > > }
> > >
> > > the returned binary value is uploaded to the DB.
> > >
> > > My main problem is that I don't know how to measure the decreased
image
> > size
> > > while its stored in the variable.
> >
> > Use http://php.net/strlen on your binary value. Use
> http://php.net/filesize
> > on your input file.
>
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> Internet Service Providers
> Ben-Nes Michael - Manager
> Tel: 972-4-6991122
> http://sites.canaan.co.il
> --------------------------
>
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