have you thought about a switch statement? haven't looked at your code, but
that would allow you a default, and then a bunch of cases, etc...

jack

-----Original Message-----
From: Jason Dulberg [mailto:[EMAIL PROTECTED]]
Sent: Thursday, October 04, 2001 1:43 AM
To: Rasmus Lerdorf
Cc: [EMAIL PROTECTED]
Subject: RE: [PHP] php in css not working with IF's


Thanks for sticking with me here and for your examples!!

So basically, I need to use AND instead of OR.

if (($site_style!=="10") && ($site_style!=="9") && ($site_style!=="8")) {
}

elseif ($site_style=="10") {
}

hrm... it didn't work.

Sorry for being such a dope about this.... :(

Jason



> Ok, you are clearly not following along here...  ;)
>
> You have (let $site_style = A for brevity):
>
> if( A!=10 OR A!=9 OR A!=8 )
>
> When A=10 this becomes:
>
> if( 10!=10 OR 10!=9 OR 10!=8 )
>      false    true     true
>
> if( false OR true OR true ) is the same as if (true)
>
> Seriously, try drawing the Venn diagram for your expression.
>
> Or try substituting common english.
>
> if Jason is not 21 or Jason is not 20 or Jason is no 19 let him into the
> cool club.
>
> Say Jason is 21, is he allowed in?  Sure he is, because one of the
> conditions for getting into the cool club is that Jason is not 20.  It
> doesn't matter that one of the other conditions says to not let Jason in.
> If the people writing the rules wanted to force all the conditions to
> apply they would have written:
>
> if Jason is not 21 AND Jason is not 20 AND Jason is not 19, let him into
> the cool club.
>
> -Rasmus
>
>

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