it's a warning, not an error...
you should check if it is set before you use it :
If(IsSet($id)) {
Do something...
}
Sincerely
berber
Visit http://www.weberdev.com Today!!!
To see where PHP might take you tomorrow.
-----Original Message-----
From: Tshering Norbu [mailto:[EMAIL PROTECTED]]
Sent: Friday, October 19, 2001 11:23 AM
To: [EMAIL PROTECTED]
Subject: [PHP] Undefined variable
Dear list,
I test the following script on local web server and it runs fine. But
when
I upload the script to the real web server I get the following
error/message, but the script works fine. Do you know why?
Here is the error/message I get:
Undefined variable : id in test.php on line 6
And here is the script file (test.php):
<html>
<body>
<?php
$db = mysql_connect("localhost", "root", "root");
mysql_select_db("penpal",$db);
if ($id)
$result = mysql_query("select * from penpal where id = $id",$db);
$myrow = mysql_fetch_array($result);
printf("<b>ID:</b> %s\n<br>", $myrow["id"]);
printf("<b>Name:</b> %s\n<br>", $myrow["name"]);
printf("<b>Age/Sex/Location:</b> %s\n<br>", $myrow["asl"]);
printf("<b>Description:</b> %s\n<br>", $myrow["description"]);
printf("<b>Email:</b> %s\n<br>", $myrow["email"]);
} else {
$result = mysql_query("select * from penpal order by id desc", $db);
if ($myrow = mysql_fetch_array($result)) {
do {
printf("<a href = \"%s?id=%s\">%s %s</a><br>\n", $PHP_SELF,
$myrow["id"],
$myrow["name"], $myrow["asl"]);
} while ($myrow = mysql_fetch_array($result));
} else {
echo "Sorry, no records";
}
}
?>
</body>
</html>
The id field in my table has the attribute: id tinyint (4)
Thanks in advance
NOBBY
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