Well for that example I'm using 0 as the index for the first element of the
array, so deleting element #2 results in 3 being deleted.  BTW to correct
myself in the second example I gave I want:

$a = (1,2,4,5) instead of (1,2,3,4).

> $a = array(1,2,3,4,5)
>
> unset($a[2]);
>
> $a now = (1, 2, NULL, 4, 5), but I want (1, 2, 3, 4).

Thanks.

David

----- Original Message -----
From: "Sam Masiello" <[EMAIL PROTECTED]>
To: "David Yee" <[EMAIL PROTECTED]>
Sent: Tuesday, October 30, 2001 10:53 AM
Subject: Re: [PHP] Quick array question


>
> Very interesting delete function......
>
> I assume $b should have values (1,3,4,5), not (1,2,4,5) :)
>
> --Sam
>
>
>
> ----- Original Message -----
> From: "David Yee" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Tuesday, October 30, 2001 2:03 PM
> Subject: [PHP] Quick array question
>
>
> Hi.  Is there an array function that deletes an array element (that's not
at
> the beginning or the end of the array) and return the resultant array?
E.g.
> this is what I want to do:
>
> $a = array(1, 2, 3, 4, 5);
>
> $b = array_element_delete_function($a, 2);
>
> $b now has 4 elements with the following values: (1, 2, 4, 5)
>
> Thanks.
>
> David
>
>
>


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