on 11/9/01 2:01 PM, Kurt Lieber at [EMAIL PROTECTED] wrote: > What you're doing doesn't make any sense. If it were to work, it would look > like the following: > > <?PHP <?PHP Query_Database( $category );?> ; ?>, > > or something similar. I think what you want to do is: > <?php > $content = query_database($category); > echo $content; > ?> > > that's using psuedo-code, of course. You'll want to substitute correct php > syntax for returning database results.
Kurt: I understand where you are coming from, and I appreciate your answer. However, I'm trying to get PHP to parse commands that are stored in a variable because I'm passing those commands to a function. Inside the function, it needs to evaluate the commands stored in the variable. Does you solution solve that or does my description clarify my problem better? Thanks, Christopher -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
