Hello all, I still having problem when use jpeg functions... I got: " testout.jpg is not a valid JPEG file in .." , with follow code: Header("Content-type: image/jpeg"); $img=ImageCreateFromJPEG("testout.jpg"); ImageJPEG($img,"a.jpg"); ImageDestroy($img);
testout.jpg was one image created by jpeg-6b after make test, I see image directly in browser (machine_name/directory/where/have/code/testout.jpg) the image, my phpinfo gives me information that gd had support for jpeg enabled .... I try with other *.jpeg files .... I try this code: Header("Content-type: image/jpeg"); $im=ImageCreate(400,200); $bcg = ImageColorAllocate($im,240,240,240); $prt = ImageColorAllocate($im,0,0,0); $rd = ImageColorAllocate($im,255,0,0); ImageFill($im,400,200,$bcg); ImageLine($im,110,85,280,85,$rd); ImageString($im,5,130,90,"--- OK ---",$prt); ImageLine($im,110,110,280,110,$rd); ImageJPEG($im,"a.jpg"); ImageDestroy($im); and the result was an empty a.jpg file ..... aaaaaaaaaaaaaaaaaaaaaaaaaaaaa. If anyone has any idea ... I already dont know what to do .... T.Y. -- Best Regards Miguel Joaquim Rodrigues Loureiro
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